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#include <vcl.h>
#include <string.h>
#include <conio.h>
#include <stdio.h>
#include <cstring.h>
#include <iostream.h>
#pragma hdrstop
#pragma argsused
int main(int argc, char* argv[])
{
//vecteurs d'entrée
int const n = 50;
string InputVector[n] = {"0", "1e-3", "2e-5", "4e-3", "7e-7", "6e-4",
"1", "4e-3", "66e-5", "43e-3", "78e-7","12e-4","2", "2e-3", "10e-5", "20e-3", "90e-7", "70e-4"};
//vecteur de sortie
string OutputVector_1[6];
string OutputVector_2[6];
string OutputVector_3[6];
string CuVa = "";
int p = -1;
int r = 0;
//lecture du vecteur d'entrée
for (int i=0; i <= n-1; i++)
{
CuVa = InputVector[i];
cout << CuVa << "\t";
if (CuVa == "0" || CuVa == "1" || CuVa == "2")
{
p++;
r = 0;
}
if (p==0)
OutputVector_1[r] = CuVa;
if (p==1)
OutputVector_2[r] = CuVa;
if (p==2)
OutputVector_3[r] = CuVa;
r++;
}
// ecriture matricielle du vecteur de sortie
int j = 0;
for (int i=0; i <= p; i++)
{
j = 0;
while(j <= 6)
{
if (i==0)
{
ShowMessage("val 1");
CuVa = OutputVector_1[j];
cout << CuVa;
}
if (i==1)
{
ShowMessage("val 2");
CuVa = OutputVector_2[j];
cout << CuVa;
}
if (i==2)
{
ShowMessage("val 3");
CuVa = OutputVector_3[j];
cout << CuVa;
}
//cout << CuVa;
if (j != 6 )
cout << "\t";
else
cout << "\n";
j++;
}
getch();
} |
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